Post by Bandage Man on Jul 20, 2017 12:43:12 GMT -5
We have our 2 Death Match Player:
JOSHUA and TREVOD
Joshua has 9 garnets. Trevor has 8 garnets.
We will begin the death match for 17 garnets and advancing.
The 8th Death Match is "Beads Horde".
In this game, players are to move the beads from the houses into their storehouse. The person with the most beads in their storehouse at the end of the game is the winner.
The rules slightly differ from the 1st time.
The board consists of two rows of six holes called the houses and two bigger holes called the storehouse. Each player has a starting row that corresponds with the letter given to them. So, Player A will start from any house from A1 to A6 and Player B will start from any house from B1 to B6.
Each player starts the game with six beads in each house at the beginning of the game. Using Random.org, we will decide who starts first.
During each player's turn, they will choose a house and move the entire contents of their house and place one bead in each of the houses in order. Once they finished placing the last piece, their turn is over even if there are beads in the final hole.
Their opponent won't need to place any bead in their opponent's house and will straight away proceed to their starting row. E.g. Player B will place one bead in A6 and then straight away put one bead in B1.
If they end up placing that bead in their own house and their opponent's house opposite them have beads in it, they get to transfer the bead that they last put as well as their opponent's into their own warehouse.However, this rule only applies when they have successfully moved. Unlike the 1st time, they do not need to go through one whole round to transfer both houses' beads to their warehouse.
E.g. Player A starts their turn and ends up back putting their last bead on A5. In B2, there are 10 beads. They will transfer the one bead in A5 and 10 beads in B2 and move it all to AH.
If they end up placing their last bead in their own empty house and their opposite opponent's house is empty, they cannot move their own bead back to their storehouse.
If a player's last bead ends at their own storehouse, they will get another turn and choose to start from any of their own house.
The player with the most beads once all the beads have been moved will be the winner of this game.
For every turn, each player will update the number of beads at each house and storehouse based on the number of beads they picked up at the house.
A1 – 6, A2 - 6, A3 – 6, A4 – 6, A5 – 6, A6 – 6, AH – 6,
B1 – 6, B2 – 6, B3 – 6, B4 – 6, B5 – 6, B6 – 6, BH – 6
I'm having sch camp until fri night so a little hard to do it live. But if you all can do it, yoi can fix a time. We will try to do it live by Sun night if not, it will be non-live
JOSHUA and TREVOD
Joshua has 9 garnets. Trevor has 8 garnets.
We will begin the death match for 17 garnets and advancing.
The 8th Death Match is "Beads Horde".
In this game, players are to move the beads from the houses into their storehouse. The person with the most beads in their storehouse at the end of the game is the winner.
The rules slightly differ from the 1st time.
The board consists of two rows of six holes called the houses and two bigger holes called the storehouse. Each player has a starting row that corresponds with the letter given to them. So, Player A will start from any house from A1 to A6 and Player B will start from any house from B1 to B6.
Each player starts the game with six beads in each house at the beginning of the game. Using Random.org, we will decide who starts first.
During each player's turn, they will choose a house and move the entire contents of their house and place one bead in each of the houses in order. Once they finished placing the last piece, their turn is over even if there are beads in the final hole.
Their opponent won't need to place any bead in their opponent's house and will straight away proceed to their starting row. E.g. Player B will place one bead in A6 and then straight away put one bead in B1.
If they end up placing that bead in their own house and their opponent's house opposite them have beads in it, they get to transfer the bead that they last put as well as their opponent's into their own warehouse.However, this rule only applies when they have successfully moved. Unlike the 1st time, they do not need to go through one whole round to transfer both houses' beads to their warehouse.
E.g. Player A starts their turn and ends up back putting their last bead on A5. In B2, there are 10 beads. They will transfer the one bead in A5 and 10 beads in B2 and move it all to AH.
If they end up placing their last bead in their own empty house and their opposite opponent's house is empty, they cannot move their own bead back to their storehouse.
If a player's last bead ends at their own storehouse, they will get another turn and choose to start from any of their own house.
The player with the most beads once all the beads have been moved will be the winner of this game.
For every turn, each player will update the number of beads at each house and storehouse based on the number of beads they picked up at the house.
A1 – 6, A2 - 6, A3 – 6, A4 – 6, A5 – 6, A6 – 6, AH – 6,
B1 – 6, B2 – 6, B3 – 6, B4 – 6, B5 – 6, B6 – 6, BH – 6
I'm having sch camp until fri night so a little hard to do it live. But if you all can do it, yoi can fix a time. We will try to do it live by Sun night if not, it will be non-live